Как отправить запрос SOAP через HTTP, используйте дайджест-аутентификацию HTTP в Java (или C#)?
У меня есть веб-сервис с URL-адресом http://192.168.0.10/services/abc?wsdl
Этот веб-сервер использует дайджест-аутентификацию с именем пользователя admin и паролем admin
Я хочу отправить запрос на этот сервер
XML-запрос SOAP - это SOAP_RQ.XML
<soapenv:Envelope
xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:log="LogsGet" xmlns:mal="MalteseGlobal" xmlns:job="JobGlobal">
<soapenv:Body>
<log:LogsGetReq Cmd="Start" OpV="01.00.00" Sev="Info to critical"/>
</soapenv:Body>
</soapenv:Envelope>
Мой код:
private static SOAPMessage createSOAPRequest(String username, String password) throws Exception {
MessageFactory messageFactory = MessageFactory.newInstance();
SOAPMessage soapMessage = messageFactory.createMessage();
SOAPPart soapPart = soapMessage.getSOAPPart();
// SOAP Envelope
SOAPEnvelope envelope = soapPart.getEnvelope();
envelope.addNamespaceDeclaration("log", "LogsGet");
envelope.addNamespaceDeclaration("mal", "MalteseGlobal");
envelope.addNamespaceDeclaration("job", "JobGlobal");
// SOAP Body
SOAPBody soapBody = envelope.getBody();
SOAPElement soapBodyElem = soapBody.addChildElement("LogsGetReq", "log");
QName Cmd = new QName("Cmd");
QName OpV = new QName("OpV");
QName Sev = new QName("Sev");
soapBodyElem.addAttribute(Cmd, "Start");
soapBodyElem.addAttribute(OpV, "01.00.00");
soapBodyElem.addAttribute(Sev, "Info to critical");
//SOAP Header
MimeHeaders hd = soapMessage.getMimeHeaders();
hd.addHeader("UsernameToken", username);
hd.addHeader("PasswordText", password);
soapMessage.saveChanges();
return soapMessage;
}
public void sendSoapRequest(String url, String username, String password) {
try {
// Create SOAP Connection
SOAPConnectionFactory soapConnectionFactory = SOAPConnectionFactory.newInstance();
SOAPConnection soapConnection = soapConnectionFactory.createConnection();
// Send SOAP Message to SOAP Server
SOAPMessage soapResponse = soapConnection.call(createSOAPRequest(username, password, txtArea), url);
// Process the SOAP Response
ByteArrayOutputStream bos = new ByteArrayOutputStream();
soapResponse.writeTo(bos);
System.out.println();
soapConnection.close();
} catch (Exception e) {
System.out.println("Error occurred while sending SOAP Request to Server");
e.printStackTrace();
}
}
Когда я отправляю запрос, я получаю сообщение ниже: Неверный ответ: (401 Требуется авторизация)
Если я отправляю запрос, используйте инструмент curl ( http://curl.haxx.se/download/curl-7.41.0.zip) с командной строкой: curl.exe -X POST http://192.168.0.10/services/Maltese - H "Content-Type: text / xml; charset = utf-8" -H "SOAPAction: LogsGet" --digest -u admin: admin -d @ SOAP_RQ.xml -v
Я получил ответное сообщение ОК.
Может ли кто-нибудь помочь мне, Как отправить запрос SOAP через HTTP с использованием JAVA (или C#)?
Спасибо
2 ответа
Решение
// I used Apache HttpClient.
// For URL, you need to find end point URL.
import org.apache.http.auth.AuthScope;
import org.apache.http.auth.UsernamePasswordCredentials;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.HttpResponse;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import java.io.PrintWriter;
import java.io.StringWriter;
// Input parameter
String username = "";
String password = "";
String url = "";
// Variables
int responseCode = 0;
String errorMessage = "";
String responseContent = "";
String content = ""
HttpResponse response;
try
{
content =
"<soapenv:Envelope xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:log=\"LogsGet\" xmlns:mal=\"MalteseGlobal\" xmlns:job=\"JobGlobal\">" +
"\n <soapenv:Body>" +
"\n <log:LogsGetReq Cmd=\"Start\" OpV=\"01.00.00\" Sev=\"Info to critical\"/>" +
"\n </soapenv:Body>" +
"\n</soapenv:Envelope>";
// Create the POST object and add the parameters
HttpPost httpPost = new HttpPost(url);
httpPost.addHeader("Content-Type", "text/xml; charset=utf-8");
// Enable preemptive authentication within HttpClient so that HttpClient will
// send the basic authentications reponse before the server gives an unauthorized reponse.
String host = httpPost.getURI().getHost();
int port = httpPost.getURI().getPort();
AuthScope authScope = new AuthScope(host, port);
DefaultHttpClient httpClient = new DefaultHttpClient();
UsernamePasswordCredentials credentials = new UsernamePasswordCredentials(username, password);
httpClient.getCredentialsProvider().setCredentials(authScope, credentials);
StringEntity input = new StringEntity(content);
input.setContentType("application/json");
httpPost.setEntity(input);
response = httpClient.execute(httpPost);
if (response != null && response.getStatusLine() != null)
{
responseCode = response.getStatusLine().getStatusCode();
responseContent = EntityUtils.toString(response.getEntity());
}
System.out.println("\n\n-----------------------------");
System.out.println("\nResponse code: " + responseCode);
System.out.println("\nResponse content: " + responseContent);
}
catch (Exception e)
{
errorMessage += "\nUnexpected Exception: " + e.getMessage();
StringWriter sWriter = new StringWriter();
PrintWriter pWriter = new PrintWriter(sWriter, true);
e.printStackTrace(pWriter);
errorMessage += "\n" + sWriter.getBuffer().toString();
errorMessage += "\n------------Error Detail------------";
errorMessage += "\n" + e;
errorMessage += "\n" + e.getMessage();
errorMessage += "\n" + e.getLocalizedMessage();
errorMessage += "\n" + e.getCause();
errorMessage += "\n" + Arrays.toString(e.getStackTrace());
errorMessage += "\n" + e.printStackTrace();
errorMessage += "\n------------------------------------";
}
finally
{
if(response)
{
EntityUtils.consume(response.getEntity());
}
}
if(errorMessage != "")
{
System.out.println("Error: " + errorMessage);
}
Если использовать C#
Я создал успешный
Мой код:
private string WebServiceCall(string url)
{
try
{
Uri myUrl = new Uri(url);
WebRequest webRequest = WebRequest.Create(myUrl);
HttpWebRequest httpWebRequest = (HttpWebRequest)webRequest;
httpWebRequest.Method = "POST";
httpWebRequest.ContentType = "text/xml; charset=utf-8";
httpWebRequest.Headers.Add("SOAPAction: LogsGet");
httpWebRequest.ProtocolVersion = HttpVersion.Version11;
//Credentials
NetworkCredential myNetworkCredential = new NetworkCredential("admin", "admin");
CredentialCache myCredentialCache = new CredentialCache();
myCredentialCache.Add(myUrl, "Digest", myNetworkCredential);
httpWebRequest.PreAuthenticate = true;
httpWebRequest.Credentials = myNetworkCredential;
Stream requestStream = httpWebRequest.GetRequestStream();
//Create Stream and Complete Request
StreamWriter streamWriter = new StreamWriter(requestStream, Encoding.ASCII);
StringBuilder soapRequest = new StringBuilder("<soapenv:Envelope xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\" ");
soapRequest.Append("xmlns:log=\"LogsGet\" xmlns:mal=\"MalteseGlobal\" xmlns:job=\"JobGlobal\">");
soapRequest.Append("<soapenv:Body>");
soapRequest.Append("<log:LogsGetReq Cmd=\"Start\" OpV=\"01.00.00\" Sev=\"Info to critical\"/>");
soapRequest.Append("</soapenv:Body></soapenv:Envelope>");
streamWriter.Write(soapRequest.ToString());
streamWriter.Close();
//Get the Response
txtRequest.Text = soapRequest.ToString();
HttpWebResponse wr = (HttpWebResponse)httpWebRequest.GetResponse();
StreamReader srd = new StreamReader(wr.GetResponseStream());
string resulXmlFromWebService = srd.ReadToEnd();
return resulXmlFromWebService;
}
catch (Exception e)
{
return e.ToString();
}
}