Разбор JSON в Excel VBA
У меня та же проблема, что и в Excel VBA: анализируемый цикл объектов JSON, но я не могу найти решение. Мой JSON имеет вложенные объекты, поэтому предлагаемые решения, такие как VBJSON и vba-json, не работают для меня. Я также исправил один из них для правильной работы, но в результате было переполнение стека вызовов из-за многих рекурсий функции doProcess.
Наилучшим решением, по-видимому, является функция jsonDecode, представленная в оригинальном сообщении. Это очень быстро и очень эффективно; моя структура объекта - все это в универсальном Объекте VBA типа JScriptTypeInfo.
Проблема на данный момент заключается в том, что я не могу определить, какова будет структура объектов, поэтому я заранее не знаю ключей, которые будут находиться в каждом общем объекте. Мне нужно пройти через общий объект VBA, чтобы получить ключи / свойства.
Если бы моя функция синтаксического анализа javascript могла вызвать функцию VBA или подпрограмму, это было бы отлично.
9 ответов
Решение
Если вы хотите построить на вершине ScriptControlВы можете добавить несколько вспомогательных методов, чтобы получить необходимую информацию. JScriptTypeInfo Объект немного неудачен: он содержит всю необходимую информацию (как вы можете видеть в окне Watch), но, кажется, невозможно достичь этого с помощью VBA. Однако движок Javascript может помочь нам:
Option Explicit
Private ScriptEngine As ScriptControl
Public Sub InitScriptEngine()
Set ScriptEngine = New ScriptControl
ScriptEngine.Language = "JScript"
ScriptEngine.AddCode "function getProperty(jsonObj, propertyName) { return jsonObj[propertyName]; } "
ScriptEngine.AddCode "function getKeys(jsonObj) { var keys = new Array(); for (var i in jsonObj) { keys.push(i); } return keys; } "
End Sub
Public Function DecodeJsonString(ByVal JsonString As String)
Set DecodeJsonString = ScriptEngine.Eval("(" + JsonString + ")")
End Function
Public Function GetProperty(ByVal JsonObject As Object, ByVal propertyName As String) As Variant
GetProperty = ScriptEngine.Run("getProperty", JsonObject, propertyName)
End Function
Public Function GetObjectProperty(ByVal JsonObject As Object, ByVal propertyName As String) As Object
Set GetObjectProperty = ScriptEngine.Run("getProperty", JsonObject, propertyName)
End Function
Public Function GetKeys(ByVal JsonObject As Object) As String()
Dim Length As Integer
Dim KeysArray() As String
Dim KeysObject As Object
Dim Index As Integer
Dim Key As Variant
Set KeysObject = ScriptEngine.Run("getKeys", JsonObject)
Length = GetProperty(KeysObject, "length")
ReDim KeysArray(Length - 1)
Index = 0
For Each Key In KeysObject
KeysArray(Index) = Key
Index = Index + 1
Next
GetKeys = KeysArray
End Function
Public Sub TestJsonAccess()
Dim JsonString As String
Dim JsonObject As Object
Dim Keys() As String
Dim Value As Variant
Dim j As Variant
InitScriptEngine
JsonString = "{""key1"": ""val1"", ""key2"": { ""key3"": ""val3"" } }"
Set JsonObject = DecodeJsonString(CStr(JsonString))
Keys = GetKeys(JsonObject)
Value = GetProperty(JsonObject, "key1")
Set Value = GetObjectProperty(JsonObject, "key2")
End Sub
Несколько заметок:
- Если
JScriptTypeInfoэкземпляр ссылается на объект Javascript,For Each ... Nextне сработает Тем не менее, он работает, если он ссылается на массив Javascript (см.GetKeysфункция). - Свойства доступа, имя которых известно только во время выполнения, используют функции
GetPropertyа такжеGetObjectProperty, - Массив Javascript предоставляет свойства
length,0,Item 0,1,Item 1и т. д. с точечной нотацией VBA (jsonObject.property), доступно только свойство длины, и только если вы объявляете переменнуюlengthсо всеми строчными буквами. В противном случае случай не совпадает, и он не найдет его. Другие свойства недопустимы в VBA. Так что лучше используйтеGetPropertyфункция. - Код использует раннее связывание. Таким образом, вы должны добавить ссылку на "Microsoft Script Control 1.0".
- Вы должны позвонить
InitScriptEngineодин раз, прежде чем использовать другие функции, чтобы сделать некоторую базовую инициализацию.
Вот еще один метод для анализа JSON в VBA, основанный на ScriptControl ActiveX, без внешних библиотек:
Sub JsonTest()
Dim Dict, Temp, Text, Keys, Items
' Converting JSON string to appropriate nested dictionaries structure
' Dictionaries have numeric keys for JSON Arrays, and string keys for JSON Objects
' Returns Nothing in case of any JSON syntax issues
Set Dict = GetJsonDict("{a:[[{stuff:'result'}]], b:''}")
' You can use For Each ... Next and For ... Next loops through keys and items
Keys = Dict.Keys
Items = Dict.Items
' Referring directly to the necessary property if sure, without any checks
MsgBox Dict("a")(0)(0)("stuff")
' Auxiliary DrillDown() function
' Drilling down the structure, sequentially checking if each level exists
Select Case False
Case DrillDown(Dict, "a", Temp, "")
Case DrillDown(Temp, 0, Temp, "")
Case DrillDown(Temp, 0, Temp, "")
Case DrillDown(Temp, "stuff", "", Text)
Case Else
' Structure is consistent, requested value found
MsgBox Text
End Select
End Sub
Function GetJsonDict(JsonString As String)
With CreateObject("ScriptControl")
.Language = "JScript"
.ExecuteStatement "function gettype(sample) {return {}.toString.call(sample).slice(8, -1)}"
.ExecuteStatement "function evaljson(json, er) {try {var sample = eval('(' + json + ')'); var type = gettype(sample); if(type != 'Array' && type != 'Object') {return er;} else {return getdict(sample);}} catch(e) {return er;}}"
.ExecuteStatement "function getdict(sample) {var type = gettype(sample); if(type != 'Array' && type != 'Object') return sample; var dict = new ActiveXObject('Scripting.Dictionary'); if(type == 'Array') {for(var key = 0; key < sample.length; key++) {dict.add(key, getdict(sample[key]));}} else {for(var key in sample) {dict.add(key, getdict(sample[key]));}} return dict;}"
Set GetJsonDict = .Run("evaljson", JsonString, Nothing)
End With
End Function
Function DrillDown(Source, Prop, Target, Value)
Select Case False
Case TypeName(Source) = "Dictionary"
Case Source.exists(Prop)
Case Else
Select Case True
Case TypeName(Source(Prop)) = "Dictionary"
Set Target = Source(Prop)
Value = Empty
Case IsObject(Source(Prop))
Set Value = Source(Prop)
Set Target = Nothing
Case Else
Value = Source(Prop)
Set Target = Nothing
End Select
DrillDown = True
Exit Function
End Select
DrillDown = False
End Function
ОБНОВИТЬ
Обратите внимание, что описанный выше подход делает систему уязвимой в некоторых случаях, поскольку он обеспечивает прямой доступ к дискам (и другим компонентам) для вредоносного кода JS через ActiveX. Предположим, вы анализируете ответ веб-сервера JSON, например JsonString = "{a:(function(){(new ActiveXObject('Scripting.FileSystemObject')).CreateTextFile('C:\\Test.txt')})()}", После оценки вы найдете новый созданный файл C:\Test.txt, Так что разбор JSON с ScriptControl ActiveX не очень хорошая идея.
Пытаясь избежать этого, я создал JSON-парсер на основе RegEx. Объекты {} представлены словарями, что позволяет использовать свойства и методы словаря: .Count, .Exists(), .Item(), .Items, .Keys, Массивы [] являются обычными массивами VB на основе нуля, так UBound() показывает количество элементов. Вот код с некоторыми примерами использования:
Option Explicit
Sub JsonTest()
Dim strJsonString As String
Dim varJson As Variant
Dim strState As String
Dim varItem As Variant
' parse JSON string to object
' root element can be the object {} or the array []
strJsonString = "{""a"":[{}, 0, ""value"", [{""stuff"":""content""}]], b:null}"
ParseJson strJsonString, varJson, strState
' checking the structure step by step
Select Case False ' if any of the checks is False, the sequence is interrupted
Case IsObject(varJson) ' if root JSON element is object {},
Case varJson.Exists("a") ' having property a,
Case IsArray(varJson("a")) ' which is array,
Case UBound(varJson("a")) >= 3 ' having not less than 4 elements,
Case IsArray(varJson("a")(3)) ' where forth element is array,
Case UBound(varJson("a")(3)) = 0 ' having the only element,
Case IsObject(varJson("a")(3)(0)) ' which is object,
Case varJson("a")(3)(0).Exists("stuff") ' having property stuff,
Case Else
MsgBox "Check the structure step by step" & vbCrLf & varJson("a")(3)(0)("stuff") ' then show the value of the last one property.
End Select
' direct access to the property if sure of structure
MsgBox "Direct access to the property" & vbCrLf & varJson.Item("a")(3)(0).Item("stuff") ' content
' traversing each element in array
For Each varItem In varJson("a")
' show the structure of the element
MsgBox "The structure of the element:" & vbCrLf & BeautifyJson(varItem)
Next
' show the full structure starting from root element
MsgBox "The full structure starting from root element:" & vbCrLf & BeautifyJson(varJson)
End Sub
Sub BeautifyTest()
' put sourse JSON string to "desktop\source.json" file
' processed JSON will be saved to "desktop\result.json" file
Dim strDesktop As String
Dim strJsonString As String
Dim varJson As Variant
Dim strState As String
Dim strResult As String
Dim lngIndent As Long
strDesktop = CreateObject("WScript.Shell").SpecialFolders.Item("Desktop")
strJsonString = ReadTextFile(strDesktop & "\source.json", -2)
ParseJson strJsonString, varJson, strState
If strState <> "Error" Then
strResult = BeautifyJson(varJson)
WriteTextFile strResult, strDesktop & "\result.json", -1
End If
CreateObject("WScript.Shell").PopUp strState, 1, , 64
End Sub
Sub ParseJson(ByVal strContent As String, varJson As Variant, strState As String)
' strContent - source JSON string
' varJson - created object or array to be returned as result
' strState - Object|Array|Error depending on processing to be returned as state
Dim objTokens As Object
Dim objRegEx As Object
Dim bMatched As Boolean
Set objTokens = CreateObject("Scripting.Dictionary")
Set objRegEx = CreateObject("VBScript.RegExp")
With objRegEx
' specification http://www.json.org/
.Global = True
.MultiLine = True
.IgnoreCase = True
.Pattern = """(?:\\""|[^""])*""(?=\s*(?:,|\:|\]|\}))"
Tokenize objTokens, objRegEx, strContent, bMatched, "str"
.Pattern = "(?:[+-])?(?:\d+\.\d*|\.\d+|\d+)e(?:[+-])?\d+(?=\s*(?:,|\]|\}))"
Tokenize objTokens, objRegEx, strContent, bMatched, "num"
.Pattern = "(?:[+-])?(?:\d+\.\d*|\.\d+|\d+)(?=\s*(?:,|\]|\}))"
Tokenize objTokens, objRegEx, strContent, bMatched, "num"
.Pattern = "\b(?:true|false|null)(?=\s*(?:,|\]|\}))"
Tokenize objTokens, objRegEx, strContent, bMatched, "cst"
.Pattern = "\b[A-Za-z_]\w*(?=\s*\:)" ' unspecified name without quotes
Tokenize objTokens, objRegEx, strContent, bMatched, "nam"
.Pattern = "\s"
strContent = .Replace(strContent, "")
.MultiLine = False
Do
bMatched = False
.Pattern = "<\d+(?:str|nam)>\:<\d+(?:str|num|obj|arr|cst)>"
Tokenize objTokens, objRegEx, strContent, bMatched, "prp"
.Pattern = "\{(?:<\d+prp>(?:,<\d+prp>)*)?\}"
Tokenize objTokens, objRegEx, strContent, bMatched, "obj"
.Pattern = "\[(?:<\d+(?:str|num|obj|arr|cst)>(?:,<\d+(?:str|num|obj|arr|cst)>)*)?\]"
Tokenize objTokens, objRegEx, strContent, bMatched, "arr"
Loop While bMatched
.Pattern = "^<\d+(?:obj|arr)>$" ' unspecified top level array
If Not (.Test(strContent) And objTokens.Exists(strContent)) Then
varJson = Null
strState = "Error"
Else
Retrieve objTokens, objRegEx, strContent, varJson
strState = IIf(IsObject(varJson), "Object", "Array")
End If
End With
End Sub
Sub Tokenize(objTokens, objRegEx, strContent, bMatched, strType)
Dim strKey As String
Dim strRes As String
Dim lngCopyIndex As Long
Dim objMatch As Object
strRes = ""
lngCopyIndex = 1
With objRegEx
For Each objMatch In .Execute(strContent)
strKey = "<" & objTokens.Count & strType & ">"
bMatched = True
With objMatch
objTokens(strKey) = .Value
strRes = strRes & Mid(strContent, lngCopyIndex, .FirstIndex - lngCopyIndex + 1) & strKey
lngCopyIndex = .FirstIndex + .Length + 1
End With
Next
strContent = strRes & Mid(strContent, lngCopyIndex, Len(strContent) - lngCopyIndex + 1)
End With
End Sub
Sub Retrieve(objTokens, objRegEx, strTokenKey, varTransfer)
Dim strContent As String
Dim strType As String
Dim objMatches As Object
Dim objMatch As Object
Dim strName As String
Dim varValue As Variant
Dim objArrayElts As Object
strType = Left(Right(strTokenKey, 4), 3)
strContent = objTokens(strTokenKey)
With objRegEx
.Global = True
Select Case strType
Case "obj"
.Pattern = "<\d+\w{3}>"
Set objMatches = .Execute(strContent)
Set varTransfer = CreateObject("Scripting.Dictionary")
For Each objMatch In objMatches
Retrieve objTokens, objRegEx, objMatch.Value, varTransfer
Next
Case "prp"
.Pattern = "<\d+\w{3}>"
Set objMatches = .Execute(strContent)
Retrieve objTokens, objRegEx, objMatches(0).Value, strName
Retrieve objTokens, objRegEx, objMatches(1).Value, varValue
If IsObject(varValue) Then
Set varTransfer(strName) = varValue
Else
varTransfer(strName) = varValue
End If
Case "arr"
.Pattern = "<\d+\w{3}>"
Set objMatches = .Execute(strContent)
Set objArrayElts = CreateObject("Scripting.Dictionary")
For Each objMatch In objMatches
Retrieve objTokens, objRegEx, objMatch.Value, varValue
If IsObject(varValue) Then
Set objArrayElts(objArrayElts.Count) = varValue
Else
objArrayElts(objArrayElts.Count) = varValue
End If
varTransfer = objArrayElts.Items
Next
Case "nam"
varTransfer = strContent
Case "str"
varTransfer = Mid(strContent, 2, Len(strContent) - 2)
varTransfer = Replace(varTransfer, "\""", """")
varTransfer = Replace(varTransfer, "\\", "\")
varTransfer = Replace(varTransfer, "\/", "/")
varTransfer = Replace(varTransfer, "\b", Chr(8))
varTransfer = Replace(varTransfer, "\f", Chr(12))
varTransfer = Replace(varTransfer, "\n", vbLf)
varTransfer = Replace(varTransfer, "\r", vbCr)
varTransfer = Replace(varTransfer, "\t", vbTab)
.Global = False
.Pattern = "\\u[0-9a-fA-F]{4}"
Do While .Test(varTransfer)
varTransfer = .Replace(varTransfer, ChrW(("&H" & Right(.Execute(varTransfer)(0).Value, 4)) * 1))
Loop
Case "num"
varTransfer = Evaluate(strContent)
Case "cst"
Select Case LCase(strContent)
Case "true"
varTransfer = True
Case "false"
varTransfer = False
Case "null"
varTransfer = Null
End Select
End Select
End With
End Sub
Function BeautifyJson(varJson As Variant) As String
Dim strResult As String
Dim lngIndent As Long
BeautifyJson = ""
lngIndent = 0
BeautyTraverse BeautifyJson, lngIndent, varJson, vbTab, 1
End Function
Sub BeautyTraverse(strResult As String, lngIndent As Long, varElement As Variant, strIndent As String, lngStep As Long)
Dim arrKeys() As Variant
Dim lngIndex As Long
Dim strTemp As String
Select Case VarType(varElement)
Case vbObject
If varElement.Count = 0 Then
strResult = strResult & "{}"
Else
strResult = strResult & "{" & vbCrLf
lngIndent = lngIndent + lngStep
arrKeys = varElement.Keys
For lngIndex = 0 To UBound(arrKeys)
strResult = strResult & String(lngIndent, strIndent) & """" & arrKeys(lngIndex) & """" & ": "
BeautyTraverse strResult, lngIndent, varElement(arrKeys(lngIndex)), strIndent, lngStep
If Not (lngIndex = UBound(arrKeys)) Then strResult = strResult & ","
strResult = strResult & vbCrLf
Next
lngIndent = lngIndent - lngStep
strResult = strResult & String(lngIndent, strIndent) & "}"
End If
Case Is >= vbArray
If UBound(varElement) = -1 Then
strResult = strResult & "[]"
Else
strResult = strResult & "[" & vbCrLf
lngIndent = lngIndent + lngStep
For lngIndex = 0 To UBound(varElement)
strResult = strResult & String(lngIndent, strIndent)
BeautyTraverse strResult, lngIndent, varElement(lngIndex), strIndent, lngStep
If Not (lngIndex = UBound(varElement)) Then strResult = strResult & ","
strResult = strResult & vbCrLf
Next
lngIndent = lngIndent - lngStep
strResult = strResult & String(lngIndent, strIndent) & "]"
End If
Case vbInteger, vbLong, vbSingle, vbDouble
strResult = strResult & varElement
Case vbNull
strResult = strResult & "Null"
Case vbBoolean
strResult = strResult & IIf(varElement, "True", "False")
Case Else
strTemp = Replace(varElement, "\""", """")
strTemp = Replace(strTemp, "\", "\\")
strTemp = Replace(strTemp, "/", "\/")
strTemp = Replace(strTemp, Chr(8), "\b")
strTemp = Replace(strTemp, Chr(12), "\f")
strTemp = Replace(strTemp, vbLf, "\n")
strTemp = Replace(strTemp, vbCr, "\r")
strTemp = Replace(strTemp, vbTab, "\t")
strResult = strResult & """" & strTemp & """"
End Select
End Sub
Function ReadTextFile(strPath As String, lngFormat As Long) As String
' lngFormat -2 - System default, -1 - Unicode, 0 - ASCII
With CreateObject("Scripting.FileSystemObject").OpenTextFile(strPath, 1, False, lngFormat)
ReadTextFile = ""
If Not .AtEndOfStream Then ReadTextFile = .ReadAll
.Close
End With
End Function
Sub WriteTextFile(strContent As String, strPath As String, lngFormat As Long)
With CreateObject("Scripting.FileSystemObject").OpenTextFile(strPath, 2, True, lngFormat)
.Write (strContent)
.Close
End With
End Sub
Проверьте последнюю версию VBA-JSON-parser на GitHub (импортируйте модуль JSON.bas в проект VBA для обработки JSON).
Еще одна возможность этого анализатора JSON RegEx заключается в том, что он работает в 64-разрядной версии Office, где ScriptControl недоступен.
UPDATE2
Однако, если вы хотите проанализировать JSON в 64-битном Office с ScriptControl, тогда этот ответ может помочь вам заставить его работать.
Поскольку Json - не что иное, как струны, с ним легко можно обращаться, если мы сможем правильно им управлять, независимо от того, насколько сложна структура. Я не думаю, что для этого нужно использовать какую-либо внешнюю библиотеку или конвертер. Вот пример, где я проанализировал данные json, используя манипуляции со строками.
Sub FetchData()
Dim str As Variant, N&, R&
With New XMLHTTP60
.Open "GET", "https://oresapp.asicanada.net/ores.imis.services/api/member/?address=&callback=angular.callbacks._0&city=&companyName=&personName=", False
.send
str = Split(.responseText, ":[{""Id"":")
End With
N = UBound(str)
For R = 1 To N
Cells(R, 1) = Split(Split(str(R), "FullName"":""")(1), """")(0)
Cells(R, 2) = Split(Split(str(R), "Phone"":""")(1), """")(0)
Cells(R, 3) = Split(Split(str(R), "Email"":""")(1), """")(0)
Next R
End Sub
Чтобы разобрать JSON в VBA без добавления огромной библиотеки в проект книги, я создал следующее решение. Это очень быстро и хранит все ключи и значения в словаре для легкого доступа:
Function ParseJSON(json$, Optional key$ = "obj") As Object
p = 1
token = Tokenize(json)
Set dic = CreateObject("Scripting.Dictionary")
If token(p) = "{" Then ParseObj key Else ParseArr key
Set ParseJSON = dic
End Function
Function ParseObj(key$)
Do: p = p + 1
Select Case token(p)
Case "]"
Case "[": ParseArr key
Case "{": ParseObj key
Case "}": key = ReducePath(key): Exit Do
Case ":": key = key & "." & token(p - 1)
Case ",": key = ReducePath(key)
Case Else: If token(p + 1) <> ":" Then dic.Add key, token(p)
End Select
Loop
End Function
Function ParseArr(key$)
Dim e&
Do: p = p + 1
Select Case token(p)
Case "}"
Case "{": ParseObj key & ArrayID(e)
Case "[": ParseArr key
Case "]": Exit Do
Case ":": key = key & ArrayID(e)
Case ",": e = e + 1
Case Else: dic.Add key & ArrayID(e), token(p)
End Select
Loop
End Function
В приведенном выше коде действительно используются несколько вспомогательных функций, но приведенный выше является его основой.
Используемая здесь стратегия заключается в использовании рекурсивного токенизатора. Мне было достаточно интересно написать статью об этом решении на Medium. Это объясняет детали.
Вот полный (но удивительно короткий) листинг кода, включая все вспомогательные функции:
'-------------------------------------------------------------------
' VBA JSON Parser
'-------------------------------------------------------------------
Option Explicit
Private p&, token, dic
Function ParseJSON(json$, Optional key$ = "obj") As Object
p = 1
token = Tokenize(json)
Set dic = CreateObject("Scripting.Dictionary")
If token(p) = "{" Then ParseObj key Else ParseArr key
Set ParseJSON = dic
End Function
Function ParseObj(key$)
Do: p = p + 1
Select Case token(p)
Case "]"
Case "[": ParseArr key
Case "{": ParseObj key
Case "}": key = ReducePath(key): Exit Do
Case ":": key = key & "." & token(p - 1)
Case ",": key = ReducePath(key)
Case Else: If token(p + 1) <> ":" Then dic.Add key, token(p)
End Select
Loop
End Function
Function ParseArr(key$)
Dim e&
Do: p = p + 1
Select Case token(p)
Case "}"
Case "{": ParseObj key & ArrayID(e)
Case "[": ParseArr key
Case "]": Exit Do
Case ":": key = key & ArrayID(e)
Case ",": e = e + 1
Case Else: dic.Add key & ArrayID(e), token(p)
End Select
Loop
End Function
'-------------------------------------------------------------------
' Support Functions
'-------------------------------------------------------------------
Function Tokenize(s$)
Const Pattern = """(([^""\\]|\\.)*)""|[+\-]?(?:0|[1-9]\d*)(?:\.\d*)?(?:[eE][+\-]?\d+)?|\w+|[^\s""']+?"
Tokenize = RExtract(s, Pattern, True)
End Function
Function RExtract(s$, Pattern, Optional bGroup1Bias As Boolean, Optional bGlobal As Boolean = True)
Dim c&, m, n, v
With CreateObject("vbscript.regexp")
.Global = bGlobal
.MultiLine = False
.IgnoreCase = True
.Pattern = Pattern
If .TEST(s) Then
Set m = .Execute(s)
ReDim v(1 To m.Count)
For Each n In m
c = c + 1
v(c) = n.value
If bGroup1Bias Then If Len(n.submatches(0)) Or n.value = """""" Then v(c) = n.submatches(0)
Next
End If
End With
RExtract = v
End Function
Function ArrayID$(e)
ArrayID = "(" & e & ")"
End Function
Function ReducePath$(key$)
If InStr(key, ".") Then ReducePath = Left(key, InStrRev(key, ".") - 1)
End Function
Function ListPaths(dic)
Dim s$, v
For Each v In dic
s = s & v & " --> " & dic(v) & vbLf
Next
Debug.Print s
End Function
Function GetFilteredValues(dic, match)
Dim c&, i&, v, w
v = dic.keys
ReDim w(1 To dic.Count)
For i = 0 To UBound(v)
If v(i) Like match Then
c = c + 1
w(c) = dic(v(i))
End If
Next
ReDim Preserve w(1 To c)
GetFilteredValues = w
End Function
Function GetFilteredTable(dic, cols)
Dim c&, i&, j&, v, w, z
v = dic.keys
z = GetFilteredValues(dic, cols(0))
ReDim w(1 To UBound(z), 1 To UBound(cols) + 1)
For j = 1 To UBound(cols) + 1
z = GetFilteredValues(dic, cols(j - 1))
For i = 1 To UBound(z)
w(i, j) = z(i)
Next
Next
GetFilteredTable = w
End Function
Function OpenTextFile$(f)
With CreateObject("ADODB.Stream")
.Charset = "utf-8"
.Open
.LoadFromFile f
OpenTextFile = .ReadText
End With
End Function
Проще всего перейти в array.myitem(0) в коде VB
мой полный ответ здесь разбираю и разбираю (сериализую)
Используйте объект this в js
ScriptEngine.AddCode "Object.prototype.myitem=function( i ) { return this[i] } ; "
Тогда вы можете перейти к array.myitem(0)
Private ScriptEngine As ScriptControl
Public Sub InitScriptEngine()
Set ScriptEngine = New ScriptControl
ScriptEngine.Language = "JScript"
ScriptEngine.AddCode "Object.prototype.myitem=function( i ) { return this[i] } ; "
Set foo = ScriptEngine.Eval("(" + "[ 1234, 2345 ]" + ")") ' JSON array
Debug.Print foo.myitem(1) ' method case sensitive!
Set foo = ScriptEngine.Eval("(" + "{ ""key1"":23 , ""key2"":2345 }" + ")") ' JSON key value
Debug.Print foo.myitem("key1") ' WTF
End Sub
Это работает для меня в Excel и больших JSON-файлах с использованием JSON-запроса, переведенного в нативную форму. https://github.com/VBA-tools/VBA-JSON Я могу разобрать узел типа "item.something" и получить значение с помощью простой команды:
MsgBox Json("item")("something")
Что хорошо
Microsoft: поскольку VBScript является подмножеством Visual Basic для приложений,...
Приведенный ниже код взят из поста Codo, если его также полезно иметь в форме класса, и можно использовать как VBScript:
class JsonParser
' adapted from: http://stackru.com/questions/6627652/parsing-json-in-excel-vba
private se
private sub Class_Initialize
set se = CreateObject("MSScriptControl.ScriptControl")
se.Language = "JScript"
se.AddCode "function getValue(jsonObj, valueName) { return jsonObj[valueName]; } "
se.AddCode "function enumKeys(jsonObj) { var keys = new Array(); for (var i in jsonObj) { keys.push(i); } return keys; } "
end sub
public function Decode(ByVal json)
set Decode = se.Eval("(" + cstr(json) + ")")
end function
public function GetValue(ByVal jsonObj, ByVal valueName)
GetValue = se.Run("getValue", jsonObj, valueName)
end function
public function GetObject(ByVal jsonObject, ByVal valueName)
set GetObjet = se.Run("getValue", jsonObject, valueName)
end function
public function EnumKeys(ByVal jsonObject)
dim length, keys, obj, idx, key
set obj = se.Run("enumKeys", jsonObject)
length = GetValue(obj, "length")
redim keys(length - 1)
idx = 0
for each key in obj
keys(idx) = key
idx = idx + 1
next
EnumKeys = keys
end function
end class
Использование:
set jp = new JsonParser
set jo = jp.Decode("{value: true}")
keys = jp.EnumKeys(jo)
value = jp.GetValue(jo, "value")
Два небольших вклада в ответ Codo:
' "recursive" version of GetObjectProperty
Public Function GetObjectProperty(ByVal JsonObject As Object, ByVal propertyName As String) As Object
Dim names() As String
Dim i As Integer
names = Split(propertyName, ".")
For i = 0 To UBound(names)
Set JsonObject = ScriptEngine.Run("getProperty", JsonObject, names(i))
Next
Set GetObjectProperty = JsonObject
End Function
' shortcut to object array
Public Function GetObjectArrayProperty(ByVal JsonObject As Object, ByVal propertyName As String) As Object()
Dim a() As Object
Dim i As Integer
Dim l As Integer
Set JsonObject = GetObjectProperty(JsonObject, propertyName)
l = GetProperty(JsonObject, "length") - 1
ReDim a(l)
For i = 0 To l
Set a(i) = GetObjectProperty(JsonObject, CStr(i))
Next
GetObjectArrayProperty = a
End Function
Так что теперь я могу делать такие вещи, как:
Dim JsonObject As Object
Dim Value() As Object
Dim i As Integer
Dim Total As Double
Set JsonObject = DecodeJsonString(CStr(request.responseText))
Value = GetObjectArrayProperty(JsonObject, "d.Data")
For i = 0 To UBound(Value)
Total = Total + Value(i).Amount
Next
Большое спасибо, Кодо.
Я только что обновил и завершил то, что вы сделали для:
- сериализовать JSON (мне нужно, чтобы внедрить JSON в текстовом документе)
добавить, удалить и обновить узел (кто знает)
Option Explicit Private ScriptEngine As ScriptControl Public Sub InitScriptEngine() Set ScriptEngine = New ScriptControl ScriptEngine.Language = "JScript" ScriptEngine.AddCode "function getProperty(jsonObj, propertyName) { return jsonObj[propertyName]; } " ScriptEngine.AddCode "function getType(jsonObj, propertyName) {return typeof(jsonObj[propertyName]);}" ScriptEngine.AddCode "function getKeys(jsonObj) { var keys = new Array(); for (var i in jsonObj) { keys.push(i); } return keys; } " ScriptEngine.AddCode "function addKey(jsonObj, propertyName, value) { jsonObj[propertyName] = value; return jsonObj;}" ScriptEngine.AddCode "function removeKey(jsonObj, propertyName) { var json = jsonObj; delete json[propertyName]; return json }" End Sub Public Function removeJSONProperty(ByVal JsonObject As Object, propertyName As String) Set removeJSONProperty = ScriptEngine.Run("removeKey", JsonObject, propertyName) End Function Public Function updateJSONPropertyValue(ByVal JsonObject As Object, propertyName As String, value As String) As Object Set updateJSONPropertyValue = ScriptEngine.Run("removeKey", JsonObject, propertyName) Set updateJSONPropertyValue = ScriptEngine.Run("addKey", JsonObject, propertyName, value) End Function Public Function addJSONPropertyValue(ByVal JsonObject As Object, propertyName As String, value As String) As Object Set addJSONPropertyValue = ScriptEngine.Run("addKey", JsonObject, propertyName, value) End Function Public Function DecodeJsonString(ByVal JsonString As String) InitScriptEngine Set DecodeJsonString = ScriptEngine.Eval("(" + JsonString + ")") End Function Public Function GetProperty(ByVal JsonObject As Object, ByVal propertyName As String) As Variant GetProperty = ScriptEngine.Run("getProperty", JsonObject, propertyName) End Function Public Function GetObjectProperty(ByVal JsonObject As Object, ByVal propertyName As String) As Object Set GetObjectProperty = ScriptEngine.Run("getProperty", JsonObject, propertyName) End Function Public Function SerializeJSONObject(ByVal JsonObject As Object) As String() Dim Length As Integer Dim KeysArray() As String Dim KeysObject As Object Dim Index As Integer Dim Key As Variant Dim tmpString As String Dim tmpJSON As Object Dim tmpJSONArray() As Variant Dim tmpJSONObject() As Variant Dim strJsonObject As String Dim tmpNbElement As Long, i As Long InitScriptEngine Set KeysObject = ScriptEngine.Run("getKeys", JsonObject) Length = GetProperty(KeysObject, "length") ReDim KeysArray(Length - 1) Index = 0 For Each Key In KeysObject tmpString = "" If ScriptEngine.Run("getType", JsonObject, Key) = "object" Then 'MsgBox "object " & SerializeJSONObject(GetObjectProperty(JsonObject, Key))(0) Set tmpJSON = GetObjectProperty(JsonObject, Key) strJsonObject = VBA.Replace(ScriptEngine.Run("getKeys", tmpJSON), " ", "") tmpNbElement = Len(strJsonObject) - Len(VBA.Replace(strJsonObject, ",", "")) If VBA.IsNumeric(Left(ScriptEngine.Run("getKeys", tmpJSON), 1)) = True Then ReDim tmpJSONArray(tmpNbElement) For i = 0 To tmpNbElement tmpJSONArray(i) = GetProperty(tmpJSON, i) Next tmpString = "[" & Join(tmpJSONArray, ",") & "]" Else tmpString = "{" & Join(SerializeJSONObject(tmpJSON), ", ") & "}" End If Else tmpString = GetProperty(JsonObject, Key) End If KeysArray(Index) = Key & ": " & tmpString Index = Index + 1 Next SerializeJSONObject = KeysArray End Function Public Function GetKeys(ByVal JsonObject As Object) As String() Dim Length As Integer Dim KeysArray() As String Dim KeysObject As Object Dim Index As Integer Dim Key As Variant InitScriptEngine Set KeysObject = ScriptEngine.Run("getKeys", JsonObject) Length = GetProperty(KeysObject, "length") ReDim KeysArray(Length - 1) Index = 0 For Each Key In KeysObject KeysArray(Index) = Key Index = Index + 1 Next GetKeys = KeysArray End Function
Здесь много хороших ответов - просто добавляю свой собственный.
У меня было требование проанализировать очень конкретную строку JSON, представляющую результаты вызова веб-API. JSON описывает список объектов и выглядит примерно так:
[
{
"property1": "foo",
"property2": "bar",
"timeOfDay": "2019-09-30T00:00:00",
"numberOfHits": 98,
"isSpecial": false,
"comment": "just to be awkward, this contains a comma"
},
{
"property1": "fool",
"property2": "barrel",
"timeOfDay": "2019-10-31T00:00:00",
"numberOfHits": 11,
"isSpecial": false,
"comment": null
},
...
]
По этому поводу следует отметить несколько моментов:
- JSON всегда должен описывать список (даже если он пустой), который должен содержать только объекты.
- Объекты в списке должны содержать только свойства простых типов (строка / дата / число / логическое значение или
null). - Значение свойства может содержать запятую, что несколько усложняет синтаксический анализ JSON, но не может содержать кавычек (потому что я слишком ленив, чтобы иметь дело с этим).
В ParseListOfObjects функция в приведенном ниже коде принимает строку JSON в качестве входных данных и возвращает Collectionпредставляющие элементы в списке. Каждый элемент представлен в видеDictionary, где ключи словаря соответствуют названиям свойств объекта. Значения автоматически преобразуются в соответствующий тип (String, Date, Double, Boolean - или Empty если значение null).
Вашему проекту VBA потребуется ссылка на Microsoft Scripting Runtime библиотека для использования Dictionary объект - хотя эту зависимость будет нетрудно удалить, если вы используете другой способ кодирования результатов.
Вот мой JSON.bas:
Option Explicit
' NOTE: a fully-featured JSON parser in VBA would be a beast.
' This simple parser only supports VERY simple JSON (which is all we need).
' Specifically, it supports JSON comprising a list of objects, each of which has only simple properties.
Private Const strSTART_OF_LIST As String = "["
Private Const strEND_OF_LIST As String = "]"
Private Const strLIST_DELIMITER As String = ","
Private Const strSTART_OF_OBJECT As String = "{"
Private Const strEND_OF_OBJECT As String = "}"
Private Const strOBJECT_PROPERTY_NAME_VALUE_SEPARATOR As String = ":"
Private Const strQUOTE As String = """"
Private Const strNULL_VALUE As String = "null"
Private Const strTRUE_VALUE As String = "true"
Private Const strFALSE_VALUE As String = "false"
Public Function ParseListOfObjects(ByVal strJson As String) As Collection
' Takes a JSON string that represents a list of objects (where each object has only simple value properties), and
' returns a collection of dictionary objects, where the keys and values of each dictionary represent the names and
' values of the JSON object properties.
Set ParseListOfObjects = New Collection
Dim strList As String: strList = Trim(strJson)
' Check we have a list
If Left(strList, Len(strSTART_OF_LIST)) <> strSTART_OF_LIST _
Or Right(strList, Len(strEND_OF_LIST)) <> strEND_OF_LIST Then
Err.Raise vbObjectError, Description:="The provided JSON does not appear to be a list (it does not start with '" & strSTART_OF_LIST & "' and end with '" & strEND_OF_LIST & "')"
End If
' Get the list item text (between the [ and ])
Dim strBody As String: strBody = Trim(Mid(strList, 1 + Len(strSTART_OF_LIST), Len(strList) - Len(strSTART_OF_LIST) - Len(strEND_OF_LIST)))
If strBody = "" Then
Exit Function
End If
' Check we have a list of objects
If Left(strBody, Len(strSTART_OF_OBJECT)) <> strSTART_OF_OBJECT Then
Err.Raise vbObjectError, Description:="The provided JSON does not appear to be a list of objects (the content of the list does not start with '" & strSTART_OF_OBJECT & "')"
End If
' We now have something like:
' {"property":"value", "property":"value"}, {"property":"value", "property":"value"}, ...
' so we can't just split on a comma to get the various items (because the items themselves have commas in them).
' HOWEVER, since we know we're dealing with very simple JSON that has no nested objects, we can split on "}," because
' that should only appear between items. That'll mean that all but the last item will be missing it's closing brace.
Dim astrItems() As String: astrItems = Split(strBody, strEND_OF_OBJECT & strLIST_DELIMITER)
Dim ixItem As Long
For ixItem = LBound(astrItems) To UBound(astrItems)
Dim strItem As String: strItem = Trim(astrItems(ixItem))
If Left(strItem, Len(strSTART_OF_OBJECT)) <> strSTART_OF_OBJECT Then
Err.Raise vbObjectError, Description:="Mal-formed list item (does not start with '" & strSTART_OF_OBJECT & "')"
End If
' Only the last item will have a closing brace (see comment above)
Dim bIsLastItem As Boolean: bIsLastItem = ixItem = UBound(astrItems)
If bIsLastItem Then
If Right(strItem, Len(strEND_OF_OBJECT)) <> strEND_OF_OBJECT Then
Err.Raise vbObjectError, Description:="Mal-formed list item (does not end with '" & strEND_OF_OBJECT & "')"
End If
End If
Dim strContent: strContent = Mid(strItem, 1 + Len(strSTART_OF_OBJECT), Len(strItem) - Len(strSTART_OF_OBJECT) - IIf(bIsLastItem, Len(strEND_OF_OBJECT), 0))
ParseListOfObjects.Add ParseObjectContent(strContent)
Next ixItem
End Function
Private Function ParseObjectContent(ByVal strContent As String) As Scripting.Dictionary
Set ParseObjectContent = New Scripting.Dictionary
ParseObjectContent.CompareMode = TextCompare
' The object content will look something like:
' "property":"value", "property":"value", ...
' ... although the value may not be in quotes, since numbers are not quoted.
' We can't assume that the property value won't contain a comma, so we can't just split the
' string on the commas, but it's reasonably safe to assume that the value won't contain further quotes
' (and we're already assuming no sub-structure).
' We'll need to scan for commas while taking quoted strings into account.
Dim ixPos As Long: ixPos = 1
Do While ixPos <= Len(strContent)
Dim strRemainder As String
' Find the opening quote for the name (names should always be quoted)
Dim ixOpeningQuote As Long: ixOpeningQuote = InStr(ixPos, strContent, strQUOTE)
If ixOpeningQuote <= 0 Then
' The only valid reason for not finding a quote is if we're at the end (though white space is permitted)
strRemainder = Trim(Mid(strContent, ixPos))
If Len(strRemainder) = 0 Then
Exit Do
End If
Err.Raise vbObjectError, Description:="Mal-formed object (the object name does not start with a quote)"
End If
' Now find the closing quote for the name, which we assume is the very next quote
Dim ixClosingQuote As Long: ixClosingQuote = InStr(ixOpeningQuote + 1, strContent, strQUOTE)
If ixClosingQuote <= 0 Then
Err.Raise vbObjectError, Description:="Mal-formed object (the object name does not end with a quote)"
End If
If ixClosingQuote - ixOpeningQuote - Len(strQUOTE) = 0 Then
Err.Raise vbObjectError, Description:="Mal-formed object (the object name is blank)"
End If
Dim strName: strName = Mid(strContent, ixOpeningQuote + Len(strQUOTE), ixClosingQuote - ixOpeningQuote - Len(strQUOTE))
' The next thing after the quote should be the colon
Dim ixNameValueSeparator As Long: ixNameValueSeparator = InStr(ixClosingQuote + Len(strQUOTE), strContent, strOBJECT_PROPERTY_NAME_VALUE_SEPARATOR)
If ixNameValueSeparator <= 0 Then
Err.Raise vbObjectError, Description:="Mal-formed object (missing '" & strOBJECT_PROPERTY_NAME_VALUE_SEPARATOR & "')"
End If
' Check that there was nothing between the closing quote and the colon
strRemainder = Trim(Mid(strContent, ixClosingQuote + Len(strQUOTE), ixNameValueSeparator - ixClosingQuote - Len(strQUOTE)))
If Len(strRemainder) > 0 Then
Err.Raise vbObjectError, Description:="Mal-formed object (unexpected content between name and '" & strOBJECT_PROPERTY_NAME_VALUE_SEPARATOR & "')"
End If
' What comes after the colon is the value, which may or may not be quoted (e.g. numbers are not quoted).
' If the very next thing we see is a quote, then it's a quoted value, and we need to find the matching
' closing quote while ignoring any commas inside the quoted value.
' If the next thing we see is NOT a quote, then it must be an unquoted value, and we can scan directly
' for the next comma.
' Either way, we're looking for a quote or a comma, whichever comes first (or neither, in which case we
' have the last - unquoted - value).
ixOpeningQuote = InStr(ixNameValueSeparator + Len(strOBJECT_PROPERTY_NAME_VALUE_SEPARATOR), strContent, strQUOTE)
Dim ixPropertySeparator As Long: ixPropertySeparator = InStr(ixNameValueSeparator + Len(strOBJECT_PROPERTY_NAME_VALUE_SEPARATOR), strContent, strLIST_DELIMITER)
If ixOpeningQuote > 0 And ixPropertySeparator > 0 Then
' Only use whichever came first
If ixOpeningQuote < ixPropertySeparator Then
ixPropertySeparator = 0
Else
ixOpeningQuote = 0
End If
End If
Dim strValue As String
Dim vValue As Variant
If ixOpeningQuote <= 0 Then ' it's not a quoted value
If ixPropertySeparator <= 0 Then ' there's no next value; this is the last one
strValue = Trim(Mid(strContent, ixNameValueSeparator + Len(strOBJECT_PROPERTY_NAME_VALUE_SEPARATOR)))
ixPos = Len(strContent) + 1
Else ' this is not the last value
strValue = Trim(Mid(strContent, ixNameValueSeparator + Len(strOBJECT_PROPERTY_NAME_VALUE_SEPARATOR), ixPropertySeparator - ixNameValueSeparator - Len(strOBJECT_PROPERTY_NAME_VALUE_SEPARATOR)))
ixPos = ixPropertySeparator + Len(strLIST_DELIMITER)
End If
vValue = ParseUnquotedValue(strValue)
Else ' It is a quoted value
' Find the corresponding closing quote, which should be the very next one
ixClosingQuote = InStr(ixOpeningQuote + Len(strQUOTE), strContent, strQUOTE)
If ixClosingQuote <= 0 Then
Err.Raise vbObjectError, Description:="Mal-formed object (the value does not end with a quote)"
End If
strValue = Mid(strContent, ixOpeningQuote + Len(strQUOTE), ixClosingQuote - ixOpeningQuote - Len(strQUOTE))
vValue = ParseQuotedValue(strValue)
' Re-scan for the property separator, in case we hit one that was part of the quoted value
ixPropertySeparator = InStr(ixClosingQuote + Len(strQUOTE), strContent, strLIST_DELIMITER)
If ixPropertySeparator <= 0 Then ' this was the last value
' Check that there's nothing between the closing quote and the end of the text
strRemainder = Trim(Mid(strContent, ixClosingQuote + Len(strQUOTE)))
If Len(strRemainder) > 0 Then
Err.Raise vbObjectError, Description:="Mal-formed object (there is content after the last value)"
End If
ixPos = Len(strContent) + 1
Else ' this is not the last value
' Check that there's nothing between the closing quote and the property separator
strRemainder = Trim(Mid(strContent, ixClosingQuote + Len(strQUOTE), ixPropertySeparator - ixClosingQuote - Len(strQUOTE)))
If Len(strRemainder) > 0 Then
Err.Raise vbObjectError, Description:="Mal-formed object (there is content after the last value)"
End If
ixPos = ixPropertySeparator + Len(strLIST_DELIMITER)
End If
End If
ParseObjectContent.Add strName, vValue
Loop
End Function
Private Function ParseUnquotedValue(ByVal strValue As String) As Variant
If StrComp(strValue, strNULL_VALUE, vbTextCompare) = 0 Then
ParseUnquotedValue = Empty
ElseIf StrComp(strValue, strTRUE_VALUE, vbTextCompare) = 0 Then
ParseUnquotedValue = True
ElseIf StrComp(strValue, strFALSE_VALUE, vbTextCompare) = 0 Then
ParseUnquotedValue = False
ElseIf IsNumeric(strValue) Then
ParseUnquotedValue = CDbl(strValue)
Else
Err.Raise vbObjectError, Description:="Mal-formed value (not null, true, false or a number)"
End If
End Function
Private Function ParseQuotedValue(ByVal strValue As String) As Variant
' Both dates and strings are quoted; we'll treat it as a date if it has the expected date format.
' Dates are in the form:
' 2019-09-30T00:00:00
If strValue Like "####-##-##T##:00:00" Then
' NOTE: we just want the date part
ParseQuotedValue = CDate(Left(strValue, Len("####-##-##")))
Else
ParseQuotedValue = strValue
End If
End Function
Простой тест:
Const strJSON As String = "[{""property1"":""foo""}]"
Dim oObjects As Collection: Set oObjects = Json.ParseListOfObjects(strJSON)
MsgBox oObjects(1)("property1") ' shows "foo"
Другой анализатор JSON на основе Regex (только декодирование)
Private Enum JsonStep
jsonString
jsonNumber
jsonTrue
jsonFalse
jsonNull
jsonOpeningBrace
jsonClosingBrace
jsonOpeningBracket
jsonClosingBracket
jsonComma
jsonColon
End Enum
Private regexp As Object
Private Function JsonStepName(ByVal json_step As JsonStep) As String
Select Case json_step
Case jsonString: JsonStepName = "'STRING'"
Case jsonNumber: JsonStepName = "'NUMBER'"
Case jsonTrue: JsonStepName = "true"
Case jsonFalse: JsonStepName = "false"
Case jsonNull: JsonStepName = "null"
Case jsonOpeningBrace: JsonStepName = "'{'"
Case jsonClosingBrace: JsonStepName = "'}'"
Case jsonOpeningBracket: JsonStepName = "'['"
Case jsonClosingBracket: JsonStepName = "']'"
Case jsonComma: JsonStepName = "','"
Case jsonColon: JsonStepName = "':'"
End Select
End Function
Private Function Unescape(ByVal str As String) As String
Dim match As Object
str = Replace$(str, "\""", """")
str = Replace$(str, "\\", "\")
str = Replace$(str, "\/", "/")
str = Replace$(str, "\b", vbBack)
str = Replace$(str, "\f", vbFormFeed)
str = Replace$(str, "\n", vbCrLf)
str = Replace$(str, "\r", vbCr)
str = Replace$(str, "\t", vbTab)
With regexp
.Global = True
.IgnoreCase = False
.MultiLine = False
.Pattern = "\\u([0-9a-fA-F]{4})"
For Each match In .Execute(str)
str = Replace$(str, match.value, ChrW$(Val("&H" + match.SubMatches(0))), match.FirstIndex + 1, 1)
Next match
End With
Unescape = str
End Function
Private Function ParseStep(ByVal str As String, _
ByRef index As Long, _
ByRef value As Variant, _
ByVal json_step As JsonStep, _
ByVal expected As Boolean) As Boolean
Dim match As Object
With regexp
.Global = False
.IgnoreCase = False
.MultiLine = False
Select Case json_step
'Case jsonString: .Pattern = "^\s*""(([^\\""]+|\\[""\\/bfnrt]|\\u[0-9a-fA-F]{4})*)""\s*"
Case jsonString: .Pattern = "^\s*""([^\\""]+|([^\\""]+|\\[""\\/bfnrt]|\\u[0-9a-fA-F]{4})*)""\s*"
Case jsonNumber: .Pattern = "^\s*(-?(0|[1-9]\d*)(\.\d+)?([eE][-+]?\d+)?)\s*"
Case jsonTrue: .Pattern = "^\s*(true)\s*"
Case jsonFalse: .Pattern = "^\s*(false)\s*"
Case jsonNull: .Pattern = "^\s*(null)\s*"
Case jsonOpeningBrace: .Pattern = "^\s*(\{)\s*"
Case jsonClosingBrace: .Pattern = "^\s*(\})\s*"
Case jsonOpeningBracket: .Pattern = "^\s*(\[)\s*"
Case jsonClosingBracket: .Pattern = "^\s*(\])\s*"
Case jsonComma: .Pattern = "^\s*(\,)\s*"
Case jsonColon: .Pattern = "^\s*(:)\s*"
End Select
Set match = .Execute(Mid$(str, index))
End With
If match.Count > 0 Then
index = index + match(0).Length
Select Case json_step
Case jsonString
If match(0).SubMatches(1) = Empty Then
value = match(0).SubMatches(0)
Else
value = Unescape(match(0).SubMatches(0))
End If
Case jsonNumber: value = Val(match(0).SubMatches(0))
Case jsonTrue: value = True
Case jsonFalse: value = False
Case jsonNull: value = Null
Case Else: value = Empty
End Select
ParseStep = True
ElseIf expected Then
Err.Raise 10001, "ParseJson", "Expecting " & JsonStepName(json_step) & " at char " & index & "."
End If
End Function
Private Function ParseValue(ByRef str As String, _
ByRef index As Long, _
ByRef value As Variant, _
ByVal expected As Boolean) As Boolean
ParseValue = True
If ParseStep(str, index, value, jsonString, False) Then Exit Function
If ParseStep(str, index, value, jsonNumber, False) Then Exit Function
If ParseObject(str, index, value, False) Then Exit Function
If ParseArray(str, index, value, False) Then Exit Function
If ParseStep(str, index, value, jsonTrue, False) Then Exit Function
If ParseStep(str, index, value, jsonFalse, False) Then Exit Function
If ParseStep(str, index, value, jsonNull, False) Then Exit Function
ParseValue = False
If expected Then
Err.Raise 10001, "ParseJson", "Expecting " & JsonStepName(jsonString) & ", " & JsonStepName(jsonNumber) & ", " & JsonStepName(jsonTrue) & ", " & JsonStepName(jsonFalse) & ", " & JsonStepName(jsonNull) & ", " & JsonStepName(jsonOpeningBrace) & ", or " & JsonStepName(jsonOpeningBracket) & " at char " & index & "."
End If
End Function
Private Function ParseObject(ByRef str As String, _
ByRef index As Long, _
ByRef obj As Variant, _
ByVal expected As Boolean) As Boolean
Dim key As Variant
Dim value As Variant
ParseObject = ParseStep(str, index, Empty, jsonOpeningBrace, expected)
If ParseObject Then
Set obj = CreateObject("Scripting.Dictionary")
If ParseStep(str, index, Empty, jsonClosingBrace, False) Then Exit Function
Do
If ParseStep(str, index, key, jsonString, True) Then
If ParseStep(str, index, Empty, jsonColon, True) Then
If ParseValue(str, index, value, True) Then
If IsObject(value) Then
Set obj.Item(key) = value
Else
obj.Item(key) = value
End If
End If
End If
End If
Loop While ParseStep(str, index, Empty, jsonComma, False)
ParseObject = ParseStep(str, index, Empty, jsonClosingBrace, True)
End If
End Function
Private Function ParseArray(ByRef str As String, _
ByRef index As Long, _
ByRef arr As Variant, _
ByVal expected As Boolean) As Boolean
Dim key As Variant
Dim value As Variant
ParseArray = ParseStep(str, index, Empty, jsonOpeningBracket, expected)
If ParseArray Then
Set arr = New Collection
If ParseStep(str, index, Empty, jsonClosingBracket, False) Then Exit Function
Do
If ParseValue(str, index, value, True) Then
arr.Add value
End If
Loop While ParseStep(str, index, Empty, jsonComma, False)
ParseArray = ParseStep(str, index, Empty, jsonClosingBracket, True)
End If
End Function
Public Function ParseJson(ByVal str As String) As Object
If regexp Is Nothing Then
Set regexp = CreateObject("VBScript.RegExp")
End If
If ParseObject(str, 1, ParseJson, False) Then Exit Function
If ParseArray(str, 1, ParseJson, False) Then Exit Function
Err.Raise 10001, "ParseJson", "Expecting " & JsonStepName(jsonOpeningBrace) & " or " & JsonStepName(jsonOpeningBracket) & "."
End Function