Ошибка MySQL 1054: неизвестный столбец 'hotels.postal_code' в 'on clause'
Я не слишком уверен, почему, но мои коды не могут работать. Я получаю ошибку 1052 или 1054. Вот мои коды. Пожалуйста помоги.
SELECT
hotels.postal_code AS ' Hotel Postal Code',
name AS 'Hotel Name',
latitude AS 'Latitude',
longitude AS 'Longitude',
address AS 'Hotel Address',
hyperlink AS 'Hotel Hyperlink',
hotels.district AS 'Hotel District',
'hotel' AS type
FROM
hotels
join
hotel_sales ON hotels.postal_code = hotel_sales.sales_id
join
postal_code_location ON hotels.district = postal_code_location.district
UNION SELECT
malls.postal_code AS ' Mall Postal Code',
name AS 'Mall Name',
latitude AS 'Latitude',
longitude AS 'Longitude',
address AS 'Mall Address',
hyperlink AS 'Mall Hyperlink',
malls.district AS 'Mall District',
'mall' AS type
FROM
malls
join
hotel_sales ON hotels.postal_code = hotel_sales.sales_id
join
postal_code_location ON hotels.district = postal_code_location.district
2 ответа
Решение
Замещать
FROM
malls
join
hotel_sales ON hotels.postal_code = hotel_sales.sales_id
КАК
FROM
malls
join
hotel_sales ON malls.postal_code = hotel_sales.sales_id
присоединение MALLS
а также HOTEL_SALES
с правой колонкой...
Таким образом, последний запрос будет..
SELECT
hotels.postal_code AS ' Hotel Postal Code',
name AS 'Hotel Name',
latitude AS 'Latitude',
longitude AS 'Longitude',
address AS 'Hotel Address',
hyperlink AS 'Hotel Hyperlink',
hotels.district AS 'Hotel District',
'hotel' AS type
FROM
hotels
join
hotel_sales ON hotels.postal_code = hotel_sales.sales_id
join
postal_code_location ON hotels.district = postal_code_location.district
UNION SELECT
malls.postal_code AS ' Mall Postal Code',
name AS 'Mall Name',
latitude AS 'Latitude',
longitude AS 'Longitude',
address AS 'Mall Address',
hyperlink AS 'Mall Hyperlink',
malls.district AS 'Mall District',
'mall' AS type
FROM
malls
join
hotel_sales ON malls.postal_code = hotel_sales.sales_id
join
postal_code_location ON hotels.district = postal_code_location.district
Эта ошибка о
Устранение неоднозначности column_id в вашем запросе
Должно быть как то так
SELECT
hotels.postal_code AS ' Hotel Postal Code',
hotels.name AS 'Hotel Name',
hotels.latitude AS 'Latitude',
....