Оберните любые HTML-теги при использовании //text() в PHP: DOMXPath

Question

У меня есть следующий HTML:

<div id="ABC">
    <i>Lorem Ipsum</i> is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book.
    <br>
    It has survived not only <b>five centuries</b>, but also the leap into electronic typesetting, remaining essentially unchanged. It was popularised in the 1960s with the release of Letraset sheets containing Lorem Ipsum passages, and more recently with <i>desktop publishing software</i> like Aldus PageMaker including versions of Lorem Ipsum.
</div>

Я использую следующий запрос для хранения содержимого ABC в массиве:

foreach ( $xpath->query('//div[@id="ABC"]/text() | //div[@id="ABC"]/i | //div[@id="ABC"]/b') as $text ) {
     $data['content'][] = $text->nodeValue; 
}

И вывод примерно такой:

   [content] => Array
        (
            [0] => Lorem Ipsum
            [1] => is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book.
            [2] => It has survived not only
            [3] => five centuries
            [4] => , but also the leap into electronic typesetting, remaining essentially unchanged. It was popularised in the 1960s with the release of Letraset sheets containing Lorem Ipsum passages, and more recently with
            [5] => desktop publishing software
            [6] => like Aldus PageMaker including versions of Lorem Ipsum.
   )

Это возможно, если я хочу вывод, как это?

   [content] => Array
        (
            [0] => Lorem Ipsum is simply dummy text of the printing and typesetting industry. Lorem Ipsum has been the industry's standard dummy text ever since the 1500s, when an unknown printer took a galley of type and scrambled it to make a type specimen book.
            [1] => It has survived not only five centuries, but also the leap into electronic typesetting, remaining essentially unchanged. It was popularised in the 1960s with the release of Letraset sheets containing Lorem Ipsum passages, and more recently with desktop publishing software like Aldus PageMaker including versions of Lorem Ipsum.
   )

Answer 1

Что вы можете сделать, это накапливать текстовые узлы в строке, пока не встретите br узел. В этот момент вы добавляете накопленную строку в ваш $data['content'] массив и сбросить строку в ничто. И в конце цикла вам также нужно добавить накопленную строку в массив, если она не пуста.

Так что цикл должен выглядеть примерно так:

$line = '';
foreach ( $xpath->query('//div[@id="ABC"]/text() | //div[@id="ABC"]/i | //div[@id="ABC"]/b  | //div[@id="ABC"]/br') as $text ) {
  if ($text->nodeName == 'br') {
    $data['content'][] = $line;
    $line = '';
  }
  else
    $line .= $text->nodeValue;
}
if ($line) $data['content'][] = $line;

Обратите внимание, что я добавил //div[@id="ABC"]/br запрос к вашему $xpath->query позвоните, чтобы br узел возвращается в цикле.