Введите код транзакции в SAP с помощью теста C# GUI

Question

У меня проблемы с вводом кода транзакции в SAP, когда я запускаю тест C#. Я не знаю, где я делаю неправильную работу.

После входа в SAP enviro я пытаюсь ввести транзакцию, но она не вводится. Это дает мне ошибку. Я перепробовал много способов.

Спасибо за любую помощь.

using System;
using System.Collections.Generic;
using System.Collections;
using System.Linq;
using System.Text;
using SAPFEWSELib;
using SAPGuiAutomated.RunProgram;

namespace SAPGuiAutomated.Program
{
    //created a class for the SAP app, connection, and session objects as well as for common methods. 
    public static class SAPActive
    {
        public static GuiApplication SapGuiApp { get; set; }
        public static GuiConnection SapConnection { get; set; }
        public static GuiSession SapSession { get; set; }

        public static void OpenSAP(string v)
        {
            GuiApplication Application;
            GuiConnection Connection;
            GuiSession Session;

            Application = (GuiApplication)System.Activator.CreateInstance(Type.GetTypeFromProgID("SapGui.ScriptingCtrl.1"));

            // How do I find the connection string that I use to connect to SAP?
            Connection = Application.OpenConnectionByConnectionString("..ipAddressOfmySAP..", false, true);
            Session = (GuiSession)Connection.Sessions.Item(0);

            Session.TestToolMode = 1;

            ((GuiTextField)Session.ActiveWindow.FindByName("RSYST-MANDT", "GuiTextField")).Text = "..client..";
            ((GuiTextField)Session.ActiveWindow.FindByName("RSYST-BNAME", "GuiTextField")).Text = "..loginName..";
            ((GuiTextField)Session.ActiveWindow.FindByName("RSYST-BCODE", "GuiPasswordField")).Text = "..password..";
            ((GuiTextField)Session.ActiveWindow.FindByName("RSYST-LANGU", "GuiTextField")).Text = "..language..";

            // Press the green checkmark button which is about the same as the enter key 
            GuiButton btn = (GuiButton)Session.ActiveWindow.FindByName("btn[0]", "GuiButton");
            btn.SetFocus();
            btn.Press();

            // Enter transaction 
            ((GuiTextField)Session.ActiveWindow.FindById("wnd[0]/tbar[0]/okcd")).Text = "se16n";

            //((GuiTextField)Session.FindById("wnd[0]/tbar[0]/okcd");
            //GuiCTextField transactionInput = (GuiCTextField)SAPActive.SapSession.ActiveWindow.FindById("wnd[0]/tbar[0]/okcd");
            //transactionInput.Text = "se16n";
            //GuiCTextField transactionInput = (GuiCTextField)SAPActive.SapSession.ActiveWindow.FindByName("okcd", "GuiCTextField");
            //transactionInput.Text = "Se16n";
            btn.Press();
        }
    }
}

- Я получил с этим: ((GuiTextField)Session.ActiveWindow.FindById("wnd[0]/tbar[0]/okcd")).Text = "se16n";

ошибка:

System.InvalidCastException
  HResult=0x80004002
  Message=Unable to cast COM object of type 'System.__ComObject' to interface type 'SAPFEWSELib.GuiTextField'. This operation failed because the QueryInterface call on the COM component for the interface with IID '{B4D89EE3-6EFD-4F4C-9F42-AD42B71C8EB7}' failed due to the following error: No such interface supported (Exception from HRESULT: 0x80004002 (E_NOINTERFACE)).
  Source=SAP_test
  StackTrace:
   at SAPGuiAutomated.Program.SAPActive.OpenSAP(String v) in C:\Users\Martin\source\repos\SAP_test\SAP_test\Program.cs:line 85
   at SAPGuiAutomated.RunProgram.Program.Main(String[] args) in C:\Users\Martin\source\repos\SAP_test\SAP_test\RunProgram.cs:line 17

- когда я использовал это GuiCTextField transactionInput = (GuiCTextField)SAPActive.SapSession.ActiveWindow.FindById("wnd[0]/tbar[0]/okcd") Я получил эту ошибку:

(GuiCTextField) SAPActive.SapSession.ActiveWindow.FindById ("WND [0]/ TBAR [0]/okcd"); '(GuiCTextField)SAPActive.SapSession.ActiveWindow.FindById("wnd[0]/tbar[0]/okcd")' вызвал исключение типа 'System.NullReferenceException' SAPFEWSELib.GuiCTextField {System.NullReferenceException}

когда это GuiCTextField transactionInput = (GuiCTextField)SAPActive.SapSession.ActiveWindow.FindByName("okcd", "GuiCTextField");Я получил эту ошибку:

(GuiCTextField) SAPActive.SapSession.ActiveWindow.FindByName ("okcd", "GuiCTextField"); '(GuiCTextField) SAPActive.SapSession.ActiveWindow.FindByName ("okcd", "GuiCTextField") "вызвало исключение типа' System.NullReferenceException 'SAPFEWSELib.GuiCTextField {System.NullReferenceException}

Answer 1

Хорошо, я нашел это:D

Session.StartTransaction("transactionCode");