Проблема кодирования при разборе XML

Question

Я пытаюсь разобрать XML с минидом (Python). У меня есть URL с моими данными XML.

Но я получаю ошибку:

DjangoUnicodeDecodeError

Кажется, это проблема кодирования при разборе!

Это мой код:

url = "http://sirh6.eolia-software.com/wscvsearch.asp"    
datasource = urllib2.urlopen(url)

data = datasource.read()#read() to get the sourcecode of the url
dom = parseString(data) 
handleElements(dom)

Мой xml:

   <!--?xml version="1.0" encoding="ISO-8859-1" ?-->
    ...
   (see the source code of the url above)

Я старался:

1-

url = "http://sirh6.eolia-software.com/wscvsearch.asp"  
datasource = urllib2.urlopen(url) 
data = datasource.read().decode('iso8859-1')
dom = parseString(data)

Я получил:

 UnicodeEncodeError
 'ascii' codec can't encode character u'\x92' in position 345: ordinal not in range(128)
 The string that could not be encoded/decoded was: nce darchi

Проследить:

File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py" in get_response
  100.                     response = callback(request, *callback_args, **callback_kwargs)
File "/usr/local/lib/python2.7/dist-packages/annoying/decorators.py" in wrapper
  74.             output = function(request, *args, **kwargs)
File "/home/astrocybernaute/projects/emploi/views.py" in parse_xml
  880.     dom = parseString(data) 
File "/usr/lib/python2.7/xml/dom/minidom.py" in parseString
  1924.         return expatbuilder.parseString(string)
File "/usr/lib/python2.7/xml/dom/expatbuilder.py" in parseString
  940.     return builder.parseString(string)
File "/usr/lib/python2.7/xml/dom/expatbuilder.py" in parseString
  223.             parser.Parse(string, True)

Exception Type: UnicodeEncodeError at /emploi/xml/
Exception Value: 'ascii' codec can't encode character u'\x92' in position 345: ordinal not in range(128) 

Спасибо