Парсим логи и магазин Dict

Файл журналов BGP: bgplog.log

Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.65: the number of BGP UPDATE messages received changed from '110376' to '110393'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.93: the number of BGP UPDATE messages received changed from '133736' to '134146'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.65: the number of BGP UPDATE messages sent changed from '108252' to '108348'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.93: the number of BGP UPDATE messages sent changed from '2094' to '2132'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.103: the number of BGP UPDATE messages sent changed from '91440' to '91462'
Host local.domain.net [11.130.55.2] with interface to BGP peer eth1-local.domain.net [11.8.44.10]: the number of BGP UPDATE messages sent changed from '1411' to '1413'
Host local.domain.net [11.130.55.2] with interface to BGP peer 10.81.244.18: the number of BGP UPDATE messages sent changed from '112347' to '112506'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.65: the number of messages received from the remote peer changed from '538672' to '538691'
Host local.domain.net [11.130.55.2] with interface to BGP peer 11.130.44.93: the number of messages received from the remote peer changed from '547397' to '547814'

Задача:

  1. Найдите конкретный IP, скажем, 11.130.44.93
  2. Любая строка соответствует указанному выше IP-адресу, разбивает строки и сохраняет определенные значения для каждого ключа.
  3. Сортировал ключ

Вот код, который я попробовал: Кажется, я застрял

import re
import os


def find(line):
    findThis = ""
    found = re.match(r'.*?11.130.44.103.*', line)
    # Find is true:
    if found:
        # found a item and adds in to findThis
        findThis = found.group()
    else:
        findThis = "NONE"
    return findThis


def generateDicts(log):
    currentDict = {}
    for line in log:
        if line.startswith(find(line)):
            currentDict = {
                "host": line.split(" ")[1][:24],
                "ip": line.split(" ", 9)[2],
                "peer": line.split(" ")[8],
                "info": line.split(" ", 9)[-1]}
        else:
            # currentDict = {"info":line.split("-",6)[-1]}
            currentDict = line


with open("bgplog.txt") as f:
    print list(generateDicts(f))

Я только получаю последнее значение и как-то не добавляю. Какой будет лучший подход?

Источник

2 ответа

Решение

Я предполагаю, что вы хотите генератор, и в этом случае вам нужно использовать yield ключевое слово. Попробуй это:

def generateDicts(log):
    for line in log:
        if line.startswith(find(line)):
            yield {
                "host": line.split(" ")[1][:24],
                "ip": line.split(" ", 9)[2],
                "peer": line.split(" ")[8],
                "info": line.split(" ", 9)[-1]}
Источник

Одним из подходов может быть добавление диктанта к списку. И не используйте регулярные выражения, если не нужно...

with open("bgplog.txt") as log:
    ip_to_search = '11.130.55.2'
    result = []

    for log_line in log:
        if ip_to_search in log_line:
            currentDict = {
                "host": log_line.split(" ")[1][:24],
                "ip": log_line.split(" ", 9)[2],
                "peer": log_line.split(" ")[8],
                "info": log_line.split(" ", 9)[-1]}
            result.append(currentDict)

    for element in result:
        print(element)
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