добавить / изменить координаты GPS на jpeg Exif с помощью piexifjs
я использую
piexifjs
to manipulate exif data of jpg images. everything works fine. but when I try to modify the gps longitude and latitudes, I am having some issues.
as on https://www.exiv2.org/tags.html, it states the datatype for gps coordinates it a
Rational
and I am having trouble getting how it works.
gps[piexif.GPSIFD.GPSLatitude] = 23.234;
gps[piexif.GPSIFD.GPSLatitudeRef] = "S";
OR
gps[piexif.GPSIFD.GPSLatitude] = [23,23,23];
gps[piexif.GPSIFD.GPSLatitudeRef] = "S";
I can add all the others like
Author
,
XPTitle
... and yet it It doesn't work at all for gps coordinates.
1 ответ
This worked for me.
It accepts in an array of dimention [3,2] eg.
[[59, 1], [26, 1], [794, 100]]
var filename1 = "image.jpg";
var filename2 = "out.jpg";
var jpeg = fs.readFileSync(filename1);
var data = jpeg.toString("binary");
var exifObj = piexif.load(data);
exifObj.GPS[piexif.GPSIFD.GPSLatitude] = degToDmsRational(23.2342);
exifObj.GPS[piexif.GPSIFD.GPSLatitudeRef] = "N";
exifObj.GPS[piexif.GPSIFD.GPSLongitude] = degToDmsRational(2.343);
exifObj.GPS[piexif.GPSIFD.GPSLongitudeRef] = "W";
var exifbytes = piexif.dump(exifObj);
var newData = piexif.insert(exifbytes, data);
var newJpeg = Buffer.from(newData, "binary");
fs.writeFileSync(filename2, newJpeg);
function degToDmsRational(degFloat) {
var minFloat = degFloat % 1 * 60
var secFloat = minFloat % 1 * 60
var deg = Math.floor(degFloat)
var min = Math.floor(minFloat)
var sec = Math.round(secFloat * 100)
deg = Math.abs(deg) * 1
min = Math.abs(min) * 1
sec = Math.abs(sec) * 1
return [[deg, 1], [min, 1], [sec, 100]]
}
thanks to https://github.com/hMatoba/piexifjs/issues/1#issuecomment-260176317